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Home/ Questions/Q 532849
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:26:51+00:00 2026-05-13T09:26:51+00:00

I would like to generate POST request to a server which requires authentication. I

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I would like to generate POST request to a server which requires authentication. I tried to use the following method:

private synchronized String CreateNewProductPOST (String urlString, String encodedString, String title, String content, Double price, String tags) {

    String data = "product[title]=" + URLEncoder.encode(title) +
                "&product[content]=" + URLEncoder.encode(content) + 
                "&product[price]=" + URLEncoder.encode(price.toString()) +
                "&tags=" + tags;
    try {
        URL url = new URL(urlString);
        URLConnection conn;
        conn = url.openConnection();
        conn.setRequestProperty ("Authorization", "Basic " + encodedString);
        conn.setDoOutput(true);
        conn.setDoInput(true);
        OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
        wr.write(data);
        wr.flush(); 
        // Get the response 
        BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); 
        String line; 
        while ((line = rd.readLine()) != null) { 
            // Process line... 
            } 
        wr.close(); 
        rd.close(); 
        return rd.toString();
    } catch (MalformedURLException e) {

        e.printStackTrace();
        return e.getMessage();
    }
    catch (IOException e) {

        e.printStackTrace();
        return e.getMessage();
    } 
}

but the server doesn’t receive the authorization data. The line which is supposed to add authorization data is the following:

conn.setRequestProperty ("Authorization", "Basic " + encodedString);

and the line

BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); 

also throws an IOException.

Anyway I would be very thankful if anyone could suggest any fix of the logic above in order to enable authorization using POST with UrlConnection.

but obviously it doesn’t work as it is supposed to although if the same logic is used for GET request everything works fine.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:26:51+00:00Added an answer on May 13, 2026 at 9:26 am

    A fine example found here. Powerlord got it right, below, for POST you need HttpURLConnection, instead.

    Below is the code to do that,

        URL url = new URL(urlString);
        URLConnection conn = url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestProperty ("Authorization", encodedCredentials);
    
        OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
    
        writer.write(data);
        writer.flush();
        String line;
        BufferedReader reader = new BufferedReader(new 
                                         InputStreamReader(conn.getInputStream()));
        while ((line = reader.readLine()) != null) {
          System.out.println(line);
        }
        writer.close();
        reader.close();
    

    Change URLConnection to HttpURLConnection, to make it POST request.

        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setRequestMethod("POST");
    

    Suggestion (…in comments):

    You might need to set these properties too,

    conn.setRequestProperty( "Content-type", "application/x-www-form-urlencoded");
    conn.setRequestProperty( "Accept", "*/*" );
    
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