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Home/ Questions/Q 1054027
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T17:20:30+00:00 2026-05-16T17:20:30+00:00

I would like to get a deeper understanding of the nuances of javascript. Take

  • 0

I would like to get a deeper understanding of the nuances of javascript.

Take the function below:

str.replace(/(\b[^:]+):'([^']+)'/g, function ($0, param, value) {
    ret[param] = value;
});
  • Why is there a need for /g?
  • What
    exactly gets passed into the
    function?
  • Where do these values come
    from?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-16T17:20:30+00:00Added an answer on May 16, 2026 at 5:20 pm

    Why is there a need for /g?

    Because presumably you will have multiple pairs on the matching string, e.g. a:'b' c:'d'

    What exactly gets passed into the function?

    The callback function gets the whole match as the first argument, the two later arguments are the capturing groups specified on your regexp.

    For example:

    "a:'b' c:'d'".replace(/(\b[^:]+):'([^']+)'/g, function ($0, param, value) {
        console.log($0, param, value);
    });
    

    The callback will be executed twice, and it will show you "a:'b'" for $0, "a" for param and "b" for value on the first execution.

    In the second execution -for the second match-, will show you "c:'d'" for $0, "c" for param and "d" for value.

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