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Home/ Questions/Q 7587891
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:47:17+00:00 2026-05-30T19:47:17+00:00

I would like to increment an ip address by a fixed value. Precisely this

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I would like to increment an ip address by a fixed value.

Precisely this is what I am trying to achieve, I have an ip address say, 192.168.0.3 and I want to increment it by 1 which would result in 192.168.0.4 or even by a fixed value, x so that it will increment my ip address by that number. so, I can have a host like 192.168.0.3+x.

I just want to know if any modules already exist for this conversion.

I tried socket.inet_aton and then socket.inet_ntoa, but I don’t know how to get that working properly. Need some help or advice on that.

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:47:19+00:00Added an answer on May 30, 2026 at 7:47 pm

    In Python 3:

    >>> import ipaddress
    >>> ipaddress.ip_address('192.168.0.4')  # accept both IPv4 and IPv6 addresses
    IPv4Address('192.168.0.4')
    >>> int(_)
    3232235524
    
    >>> ipaddress.ip_address('192.168.0.4') + 256
    IPv4Address('192.168.1.4')
    

    In reverse:

    >>> ipaddress.ip_address(3232235524)
    IPv4Address('192.168.0.4')
    >>> str(_)
    '192.168.0.4'
    
    >>> ipaddress.ip_address('192.168.0.4') -1
    IPv4Address('192.168.0.3')
    

    Python 2/3

    You could use struct module to unpack the result of inet_aton() e.g.,

    import struct, socket
    
    # x.x.x.x string -> integer
    ip2int = lambda ipstr: struct.unpack('!I', socket.inet_aton(ipstr))[0]
    print(ip2int("192.168.0.4"))
    # -> 3232235524
    

    In reverse:

    int2ip = lambda n: socket.inet_ntoa(struct.pack('!I', n))
    print(int2ip(3232235525))
    # -> 192.168.0.5
    
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