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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:35:55+00:00 2026-05-13T18:35:55+00:00

I would like to introduce some assembly code into a c99 codebase. I want

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I would like to introduce some assembly code into a c99 codebase. I want to use the UMULL instruction from the ARM CPU to multiply 2 uint32_t and get the result immediately into a uint64_t.

Now a uint64_t needs 2 registers, so how do I specify the output and the constraints of the asm block?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:35:56+00:00Added an answer on May 13, 2026 at 6:35 pm

    Good question!

    The following code outputs what you want using GCC -O or higher without resorting to assembler:

    uint32_t a, b;
    uint64_t c;
    …
    c = (uint64_t)a * (uint64_t)b;
    

    or if you feel you must use machine-specific asm, you can go:

    uint32_t a, b;
    uint64_t c;

    asm (“umull %Q0, %R0, %1, %2” : “=r”(c) : “r”(a), “r”(b));

    c‘s register name is the first of the register pair, and %Q and %R pick out the lower and upper 32-bit registers of the pair. See gcc/config/arm/arm.md -> umulsidi3 for an example.

    However, if you can stay in C, that gives the optimizer a chance to do more and is kinder on readers of your program.

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