I would like to join two xml files as illustrated below. However the question i have is how do you do this with having an ID to join with. I want to do the join in regards to POSITION and not id. How would you do this for the following files?
File 1:
<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
<title>Title1</title>
<description>Description1</description>
</data>
<data>
<title>Title2</title>
<description>Description2</description>
</data>
</catalog>
File 2:
<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
<author>Author1</author>
<date>12/34/5678</date>
</data>
<data>
<author>Author2</author>
<date>87/65/4321</date>
</data>
</catalog>
Output:
<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
<title>Title1</title>
<description>Description1</description>
<author>Author1</author>
<date>12/34/5678</date>
</data>
<data>
<title>Title2</title>
<description>Description2</description>
<author>Author2</author>
<date>87/65/4321</date>
</data>
</catalog>
I know how to do this if you have a common ID field using the XSLT below, however how do you join on POSITION?
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="ISO-8859-1" indent="yes" />
<xsl:variable name="with" select="'File2.xml'" />
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="scene">
<xsl:copy>
<xsl:apply-templates select="@*|node()" />
<xsl:variable name="info" select="document($with)/catalog/data[id=current()/id]/." />
<xsl:for-each select="$info/*">
<xsl:if test="name()!='myid'">
<xsl:copy-of select="." />
</xsl:if>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:transform>
1 Answer