Question

I would like to keep my dialog open when I press a button.
At the moment it’s closing.

AlertDialog.Builder builder = new AlertDialog.Builder(this);

builder.setMessage("Are you sure you want to exit?")

   .setCancelable(false)
   .setPositiveButton("Yes", new DialogInterface.OnClickListener() {
       public void onClick(DialogInterface dialog, int id) {
            MyActivity.this.finish();
       }
   })
   .setNegativeButton("No", new DialogInterface.OnClickListener() {
       public void onClick(DialogInterface dialog, int id) {
            dialog.cancel();
       }
   });
AlertDialog alert = builder.create();

Answer 1

Yes, you can. You basically need to:

1. Create the dialog with DialogBuilder
2. show() the dialog
3. Find the buttons in the dialog shown and override their onClickListener

So, create a listener class:

class CustomListener implements View.OnClickListener {
  private final Dialog dialog;

  public CustomListener(Dialog dialog) {
    this.dialog = dialog;
  }

  @Override
  public void onClick(View v) {

    // Do whatever you want here

    // If you want to close the dialog, uncomment the line below
    //dialog.dismiss();
  }
}

Then when showing the dialog use:

AlertDialog dialog = dialogBuilder.create();
dialog.show();
Button theButton = dialog.getButton(DialogInterface.BUTTON_POSITIVE);
theButton.setOnClickListener(new CustomListener(dialog));

Remember, you need to show the dialog otherwise the button will not be findable. Also, be sure to change DialogInterface.BUTTON_POSITIVE to whatever value you used to add the button. Also note that when adding the buttons in the DialogBuilder you will need to provide onClickListeners – you can not add the custom listener in there, though – the dialog will still dismiss if you do not override the listeners after show() is called.