Question

I would like to know how can i use variable here instead of constant. for ex
I have this statement

<link rel="stylesheet" type="text/css" href="<?php echo $this->getSkinUrl('css/abc.css')?>"/>

Now Instead of abc.css , I want tomake it variable instead of hardcode value
like $A = "abc.css" ;
So statement should look like ==>

$A = "abc.css" ;
<link rel="stylesheet" type="text/css" href="<?php echo $this->getSkinUrl('css/$A')?>"/>

Please guide me, I’m not able to do it.

Answer 1

Only code between <?php and ?> marks is considered and processed as PHP code. And you placed $A = "abc.css" ; outside these marks. So the code in <link> tag is trying to work with undeclared variable.

Also, only variables in double quoted strings are replaced.