Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7247861
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T22:03:44+00:00 2026-05-28T22:03:44+00:00

I would like to know how can we arrange the three select box, with

  • 0

I would like to know how can we arrange the three select box, with having some options, it will be configured according to the previous select box value.

Please look at the code which we applied for our program.

<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function () {

var rtype = $("#rtype").val();
var rarray = rtype.split(' ');

var max_adults = rarray[1];
var min_adults = rarray[0];

//var max_adults = 3;
//var min_adults = 2;

$('#rooms').change(function(){
var room_num = $(this).val();
var options = '';
for (var i = min_adults * room_num; i <= max_adults * room_num; i++) { options += '<option value="'+i+'">'+i+'</option>' } $('#person').html(options); }); $('#rooms').change(); });
</script>

</head>
<body>Room Type <select name="rtype" id="rtype"><option Selected value="">Select</option><option value="2 3">Room 2-3</option> <option value="3 4">Room 3-4</option></select> Category: <select name="rooms" id="rooms"> <option Selected value="">Select</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option><option value="5">5</option><option value="6">6</option><option value="7">7</option><option value="8">8</option> </select>Persons<select name="person" id="person"> </select></body>

Above this code is working fine if we remove the code for “rtype” ID, and entered the hard coded value to the query like this.

var max_adults = 3;
var min_adults = 2;

but we likt to update this value when we change the “rtype” id, the value for the an option is ( 2 3), we just have to split these value in to two part, the higher one will put into ” var max_adults”, and lower one will go to “var min_adult”.

Please give me the proper solution, how can we arrange the codes accordingly.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T22:03:45+00:00Added an answer on May 28, 2026 at 10:03 pm

    You need to put the rtype code inside the change event handler tof the #rooms element:

    $(function () {
    
        $('#rooms').change(function(){
    
            //get the `#rtype` value
            var rtype = $("#rtype").val();
    
            //check to make sure the `#rtype` value isn't an empty string
            if (rtype != '') {
    
                var room_num   = $(this).val(),
                    rarray     = rtype.split(' '),
                    options    = '',
                    max_adults = rarray[1],
                    min_adults = rarray[0];
    
                for (var i = min_adults * room_num; i <= max_adults * room_num; i++) {
                    options += '<option value="'+i+'">'+i+'</option>';
                }
    
                $('#person').html(options);
    
            } else {
    
                //since no `#rtype` value was found alert the user
                alert('Please Select a Room Type');
    
            }
    
        //trigger the change event by chaining rather than re-selecting the same element
        }).change();
    
    });
    

    Update

    To make one element appear when the other changes, add this to the document.ready event handler:

    $('#rtype').change(function () {
    
        //if a value has not been selected then hide the `#rooms` element, otherwise show it
        if (this.value == '') {
            $('#rooms').hide();
        } else {
            $('#rooms').show();
        }
    });
    

    You then need to add the following CSS for the #rooms element:

    #rooms {
        display : none;
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

i would like know some reference. I know i can googling it. but prefer
I would like to know how can I use jQuery to select multiple items
I would like to know how can make make an ELEMENT float according to
I would like to know how can i center this box? HTML Code: <div
I would like to know where can I find the code which eclipse uses
I would like to know how Can I paas Page as Ref Parameter to
I would like to know how can i read a value of input text
I would like to know how can I use tinyint in SQL Server 2005
I am new here. I would like to know how can I display HTML
I would like to know if I can open 2 different diagrams using MS

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.