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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:20:23+00:00 2026-05-13T10:20:23+00:00

I would like to know how to parse a JSON feed by items (eg.

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I would like to know how to parse a JSON feed by items (eg. url / title / description for each item). I have had a look to the doc / api but, it didn’t help me.

This is what I got so far

import com.google.gson.Gson;
import com.google.gson.JsonObject;

public class ImportSources extends Job {
    public void doJob() throws IOException {
        String json = stringOfUrl("http://feed.test/all.json");
        JsonObject jobj = new Gson().fromJson(json, JsonObject.class);
        Logger.info(jobj.get("responseData").toString());
    }
    public static String stringOfUrl(String addr) throws IOException {
        ByteArrayOutputStream output = new ByteArrayOutputStream();
        URL url = new URL(addr);
        IOUtils.copy(url.openStream(), output);
        return output.toString();
    }
}   
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  1. Editorial Team
    Editorial Team
    2026-05-13T10:20:23+00:00Added an answer on May 13, 2026 at 10:20 am

    Depends on the actual JSON format. You can in fact just create a custom Javabean class which matches the JSON format. Any fields in JSON can be mapped as String, Integer, Boolean, etc Javabean properties. Any arrays can be mapped as List properties. Any objects can be mapped as another nested Javabean property. It greatly eases further processing in Java.

    Without a JSON string example from your side, it’s only guessing how it would look like, so I can’t give a basic example here. But I’ve posted similar answers before here, you may find it useful:

    • Converting JSON to Java
    • Generate Java class from JSON?

    Gson has also an User Guide, you may find it useful as well.

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