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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:55:56+00:00 2026-05-11T17:55:56+00:00

I would like to know if there’s an efficient algorithm to find the greatest

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I would like to know if there’s an efficient algorithm to find the greatest m elements in an N x N matrix, with a method header like this:

double[] greatestValues(double[][] matrix, int numberOfElements);

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:55:56+00:00Added an answer on May 11, 2026 at 5:55 pm

    If you treat the N x N matrix as an array of N x N items you can apply one of the following techniques:

    Direct application of the quick sort based selection algorithm The quick
    sort based selection algorithm can be
    used to find k smallest or k largest
    elements. To find k smallest elements
    find the kth smallest element using
    the median of medians quick sort based
    algorithm. After the partition that
    finds the kth smallest element, all
    the elements smaller than the kth
    smaller element will be present left
    to the kth element and all element
    larger will be present right to the
    kth smallest element. Thus all
    elements from 1st to kth element
    inclusive constitute the k smallest
    elements. The time complexity is
    linear in n, the total number of
    elements.

    Data structure based solutions Another simple method is to add each
    element of the list into an ordered
    set data structure, such as a heap or
    self-balancing binary search tree,
    with at most k elements. Whenever the
    data structure has more than k
    elements, we remove the largest
    element, which can be done in O(log k)
    time. Each insertion operation also
    takes O(log k) time, resulting in
    O(nlog k) time overall.

    It is possible to transform the list
    into a heap in Θ(n) time, and then
    traverse the heap using a modified
    Breadth-first search algorithm that
    places the elements in a Priority
    Queue (instead of the ordinary queue
    that is normally used in a BFS), and
    terminate the scan after traversing
    exactly k elements. As the queue size
    remains O(k) throughout the traversal,
    it would require O(klog k) time to
    complete, leading to a time bound of
    O(n + klog k) on this algorithm.

    From here.

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