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Home/ Questions/Q 5935357
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:14:33+00:00 2026-05-22T15:14:33+00:00

i would like to know the difference between this two methods for initializing the

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i would like to know the difference between this two methods for initializing the object of a class

Method 1 (Using Scope resolution operator) :

Test::foo();

Method 2 (creating an instance of an object):

$test = new Test;
$test->foo();

also what is this -> operator called?

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:14:34+00:00Added an answer on May 22, 2026 at 3:14 pm

    Test::foo() is merely statically calling a method of a class, it doesn’t do anything with objects. It might initialize static values in the class, but you don’t usually use static initializers. A static initializer may be used internally in the case of Singletons, but you should never call a public static initializer like this.

    $test = new Test is actually instantiating an object, in which process it is likely initialized.

    Please note the difference between initialize (setting up the initial state of an object/class/variable) and instantiate (create an object instance from a class).

    -> is the T_OBJECT_OPERATOR.

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