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Home/ Questions/Q 334941
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:06:08+00:00 2026-05-12T10:06:08+00:00

I would like to know the .ini config file setup to make a route

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I would like to know the .ini config file setup to make a route wherein the page number parameter is optional so that

http://news.mysite.com/national
http://news.mysite.com/national/1

point to the same page.

I have the code as follows

resources.router.routes.news_list.type = "Zend_Controller_Router_Route_Regex"
resources.router.routes.news_list.route = "([a-zA-Z0-9\-]+)/([0-9\-]+)"
resources.router.routes.news_list.defaults.module = "news"
resources.router.routes.news_list.defaults.controller = "index"
resources.router.routes.news_list.defaults.action = "category"
resources.router.routes.news_list.defaults.page = 1
resources.router.routes.news_list.map.1 = "categ"
resources.router.routes.news_list.map.2 = "page"
resources.router.routes.news_list.reverse = "%s/%s"

can some1 help me out with a solution to modify this code to make it work for both urls

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:06:09+00:00Added an answer on May 12, 2026 at 10:06 am

    You can do this without the regex route using:

    routes.news_list.route = ":action/:page"
    routes.news_list.defaults.module = "news"
    routes.news_list.defaults.controller = "index"
    routes.news_list.defaults.action = "category"
    routes.news_list.defaults.page = 1
    

    I assume that you want every request to go to the “news” module and the “index” controller. Only the action and the page are variable in the url.

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