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Home/ Questions/Q 598959
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:26:45+00:00 2026-05-13T16:26:45+00:00

I would like to know the rules specified by the C++ language standard for

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I would like to know the rules specified by the C++ language standard for situations like:

long x = 200;
short y = static_cast<short>(x);

Is y guaranteed to be 200, or does the standard leave this up to the implementation to decide? How well do various compilers adhere to the standard?

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:26:46+00:00Added an answer on May 13, 2026 at 4:26 pm

    In this case the static_cast<> is an ‘explicit type conversion. the standard has this to say about integral conversions in 4.7/3 “Integral conversions”:

    If the destination type is signed, the value is unchanged if it can be represented in the destination type (and bit-field width); otherwise, the value is implementation-defined.

    Since short is guaranteed to be able to hold the value 200 (short must be at least 16 bits), then for your specific example the answer is yes.

    Various compilers adhere to this behavior quite well – it’s been that way since the pre-ANSI days of C, and so much code depends on the behavior that compiler vendors seem reluctant to even issue warnings about the possibility of truncation.

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