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Home/ Questions/Q 841575
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T05:49:07+00:00 2026-05-15T05:49:07+00:00

I would like to know what the best way (performance wise) to access a

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I would like to know what the best way (performance wise) to access a large data structure is.
There are about hundred ways to do it but what is the most accessible for the compiler to optimize?

One can access a value by

foo[someindex].bar[indexlist[i].subelement[j]].baz[0]

or create some pointer aliases like

sometype_t* tmpfoo = &foo[someindex];
tmpfoo->bar[indexlist[i].subelement[j]].baz[0]

or create reference aliases like

sometype_t &tmpfoo = foo[someindex];
tmpfoo.bar[indexlist[i].subelement[j]].baz[0]

and so forth…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T05:49:07+00:00Added an answer on May 15, 2026 at 5:49 am

    As a personal preference, I generally find it easier to read and understadn if there are fewer nested levels to traverse. Thus, I tend to use the …

    SomeType  *pSomeType = &asManyLevelsAsItMakesSense[someIndex];
    pSomeType->subSomeNestedLevels = ...;
    

    I find this particularly useful when dealing with deep nested structures in loops. Identify the invariant nested parts and hoist it out of the loop.

    SomeType  *pSomeType = &...;
    for (i = 0; i < N; i++)
        pSomeType->field[i] = ...;
    

    As always, it is worth your while to know your compiler and what it actually generates. Sometimes you may be stuck with a compiler for your project that does no optimization at all and so little things like this can make a difference (but don’t assume that it will).

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