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Home/ Questions/Q 541727
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:22:22+00:00 2026-05-13T10:22:22+00:00

I would like to know whether the actual code of a C# class gets

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I would like to know whether the actual code of a C# class gets loaded in RAM when you instantiate the class?

So for example if I have 2 Classes CLASS A , CLASS B, where class A has 10000 lines of code but just 1 field, an int. And class B has 10 lines of code and also 1 field an int as well. If I instantiate Class A will it take more RAM than Class B due to its lines of code ?

A supplementary question, If the lines of code are loaded in memory together with the class, will they be loaded for every instance of the class? or just once for all the instances?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:22:22+00:00Added an answer on May 13, 2026 at 10:22 am

    In the desktop framework, I believe methods are JITted on a method-by-method basis. I don’t know whether the IL for a class is completely loaded into RAM when the class is first loaded, or whether they’re just memory mapped to the assembly file.

    Either way, you get a single copy for all instances – at least for non-generic types. For generic types (and methods) it gets slightly more complicated – there’s one JIT representation for all reference type type arguments, and one for each value type type argument. So List<string> and List<Stream> share native code, but List<int> and List<Guid> don’t. (Extrapolate as appropriate for types with more than one generic type parameter.) You still only get one copy for all instances of the same constructed type though – objects don’t come with their own copy of the native code.

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