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Home/ Questions/Q 946559
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T22:56:14+00:00 2026-05-15T22:56:14+00:00

I would like to open a file and read a line from it. There

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I would like to open a file and read a line from it. There will be only one line in the file so I don’t really need to worry about looping, although for future reference it would be nice to know how to read multiple lines.

int main(int argc, const char* argv[]) {

    // argv[1] holds the file name from the command prompt

    int number = 0; // number must be positive!

    // create input file stream and open file
    ifstream ifs;
    ifs.open(argv[1]);

    if (ifs == NULL) {
        // Unable to open file
        exit(1);
    } else {
        // file opened
        // read file and get number
        ...?
        // done using file, close it
        ifs.close();
    }
}

How would I do this? Also, am I handling the file open correctly in terms of successful open?

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T22:56:15+00:00Added an answer on May 15, 2026 at 10:56 pm

    A couple of things:

    1. You can read a number with the >> stream extraction operator: ifs >> number.

    2. The standard library function getline will read a line from a file, if you want a full line of text.

    3. To check if the file opened, just write if (ifs) or if (!ifs). Leave out the == NULL.

    4. You don’t need to explicitly close the file at the end. That will happen automatically when the ifs variable goes out of scope.

    Revised code:

    if (!ifs) {
        // Unable to open file.
    } else if (ifs >> number) {
        // Read the number.
    } else {
        // Failed to read number.
    }
    
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