Question

I would like to perform this calculation wihout the bitwise operator.

unsigned result = (1u << 5);

The result will be 32. I know that’s converting the binary 1 to 100000 but I would like to perform the same thing without bitwise operations.

Answer 1

Since you know that 2⁵ is 32, you could just use:

unsigned int result = 1u * 32u; // or just 32u if it's always '1u *'.

Otherwise, if you just want to use the bitshift value, there are two ways. The first is a loop:

unsigned result = 1u;
for (size_t i = 0; i < 5; result *= 2u, i++);

or a non-loop version:

static unsigned int shft[] = {1u, 2u, 4u, 8u, 16u, 32u, ... };
unsigned int result = 1u * shft[5]; // or just shft[5] if it's always '1u *'.