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Home/ Questions/Q 8904865
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T02:14:52+00:00 2026-06-15T02:14:52+00:00

I would like to preserve array bounds in associate block as: integer a(2:4,2) associate

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I would like to preserve array bounds in associate block as:

integer a(2:4,2)
associate (b => a(:,1))
    print *, lbound(b), ubound(b)
end associate

I expect the bounds of b is 2 and 4, but in fact they are 1 and 3. How to do this? Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-06-15T02:14:54+00:00Added an answer on June 15, 2026 at 2:14 am

    You are associating to a subarray, its boundaries always start at 1. Try

     print *, lbound(a(:,1),1)
    

    AFAIK you can not use the pointer remapping trick in associate construct. Specifically: “If the selector is an array, the associating entity is an array with a lower bound for each dimension equal to the value of the intrinsic LBOUND(selector).“

    But you can of course use pointers

    integer,target :: a(2:4,2)
    
    integer,pointer :: c(:)
    
    
    associate (b => a(:,1))
        print *, lbound(b), ubound(b)
    end associate
    
    c(2:4) => a(:,1)
    print *, lbound(c), ubound(c)
    
    end
    
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