Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 126763
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T05:22:10+00:00 2026-05-11T05:22:10+00:00

I would like to provide a WHERE condition on an inner query by specifying

  • 0

I would like to provide a WHERE condition on an inner query by specifying innertable.id = outertable.id. However, MySQL (5.0.45) reports ‘Unknown column ‘outertable.id’ in ‘where clause”. Is this type of query possible?

The inner query is pivoting rows to columns using a GROUP BY. This could be entirely be performed in the outer query, but would possibly incur additional overhead due to the extra joins.

Alternatively, I can leave off the WHERE condition in the inner query and instead specify an ON outertable.id = innerquery.id, but it would then fetch the entire inner query rowset to join again the outer, which is inefficient.

The actual SQL appears below:

select t.ticketid, u.userid, t.fullname, u.loginapi_userid, t.email, tp.subject, tp.contents, a.PhoneNumber, a.Location, a.Extension, a.BusinessUnit, a.Department from swtickets t inner join swticketposts tp on t.ticketid = tp.ticketid inner join swusers u on t.userid = u.userid left join   (   select   cfv.typeid,   min(case cfv.customfieldid when 1 then cfv.fieldvalue end) as 'PhoneNumber',   min(case cfv.customfieldid when 3 then cfv.fieldvalue end) as 'Location',   min(case cfv.customfieldid when 5 then cfv.fieldvalue end) as 'Extension',   min(case cfv.customfieldid when 8 then cfv.fieldvalue end) as 'BusinessUnit',   min(case cfv.customfieldid when 9 then cfv.fieldvalue end) as 'Department'   from swcustomfieldvalues cfv   where cfv.typeid = t.ticketid   group by cfv.typeid   ) as a on 1 = 1 where t.ticketid = 2458; 
  • 1 1 Answer
  • 1 View
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T05:22:10+00:00Added an answer on May 11, 2026 at 5:22 am

    The answer to your question is no, it is not possible to reference correlation names as you are doing. The derived table is produced by your inner query before the outer query starts evaluating joins. So the correlation names like t, tp, and u are not available to the inner query.

    To solve this, I’d recommend using the same constant integer value in the inner query, and then join the derived table in the outer query using a real condition instead of 1=1.

    SELECT t.ticketid, u.userid, t.fullname, u.loginapi_userid, t.email,   tp.subject, tp.contents, a.PhoneNumber, a.Location, a.Extension,   a.BusinessUnit, a.Department FROM swtickets t  INNER JOIN swticketposts tp ON (t.ticketid = tp.ticketid)  INNER JOIN swusers u ON (t.userid = u.userid)  LEFT OUTER JOIN (   SELECT cfv.typeid,     MIN(CASE cfv.customfieldid WHEN 1 THEN cfv.fieldvalue END) AS 'PhoneNumber',     MIN(CASE cfv.customfieldid WHEN 3 THEN cfv.fieldvalue END) AS 'Location',     MIN(CASE cfv.customfieldid WHEN 5 THEN cfv.fieldvalue END) AS 'Extension',     MIN(CASE cfv.customfieldid WHEN 8 THEN cfv.fieldvalue END) AS 'BusinessUnit',     MIN(CASE cfv.customfieldid WHEN 9 THEN cfv.fieldvalue END) AS 'Department'   FROM swcustomfieldvalues cfv   WHERE cfv.typeid = 2458   GROUP BY cfv.typeid   ) AS a ON (a.typeid = t.ticketid) WHERE t.ticketid = 2458; 
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 113k
  • Answers 113k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer You could use a counter: $i = 0; $len =… May 11, 2026 at 10:06 pm
  • Editorial Team
    Editorial Team added an answer To detect a "shake" you would check the g-force generated.… May 11, 2026 at 10:06 pm
  • Editorial Team
    Editorial Team added an answer I resolved this problem by replacing all instances of COMCTL32.OCX,… May 11, 2026 at 10:06 pm

Related Questions

I am writing a (very small) framework for checking pre- and postconditions of methods.
I am trying to create a data access layer using t4 and C#. I
I have a set of Oracle tables that describe information about property owners. Owner
I'm trying to compile code from an open source project, and I'm running into

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.