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Home/ Questions/Q 8909667
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T03:29:24+00:00 2026-06-15T03:29:24+00:00

I would like to rearrange an array of objects in javascript, which looks like

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I would like to rearrange an array of objects in javascript, which looks like this:

[{ year: "1950-12-20", product: ["product 1", "product 2, "product 3"] }, { year: "1951-12-20", product: ["product 3", "product 2"] }, { year: "1952-12-20", product: ["product 3", "product 4"] }]

so that I get two arrays, one with the products and one with the years when they appear.

a = ["product 1", "product 2", "product 3", "product 4"]
b = ["1950-12-20", [ "1950-12-20, "1951-12-20"],["1950-12-20", "1951-12-20", "1952-12-20"],"1952-12-20"]

I have tried to loop through each object through nestled for-loops, but how do I treat the array of strings in the object array in a nice way?

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  1. Editorial Team
    Editorial Team
    2026-06-15T03:29:25+00:00Added an answer on June 15, 2026 at 3:29 am

    I don’t know what kind of loop you have tested, but this type of code is not so long for what has to be done :

    var data = [{ year: "1950-12-20", product: ["product 1", "product 2", "product 3"] }, { year: "1951-12-20", product: ["product 3", "product 2"] }, { year: "1952-12-20", product: ["product 3", "product 4"] }];
    
    var nbData = data.length, iData;
    var years = [], products = [], dictProductsYear = {};
    var nbProducts, iProduct, p;
    
    
    // Loop through years
    for(iData = 0; iData < nbData; iData ++) {
        products = data[iData].product;
        nbProducts = products.length;
    
        // Add the current year to the concerned products
        for(iProduct = 0; iProduct < nbProducts; iProduct ++) {
            p = products[iProduct];
    
            // Registered product
            if(dictProductsYear[p]) dictProductsYear[p].push(data[iData].year);
            // Unregistered one
            else dictProductsYear[p] = [ data[iData].year ];
        }
    }
    
    var yearList = [], productList = [];
    
    // Flatten the dictionary in 2 lists
    for(p in dictProductsYear) {
        productList.push(p);
        yearList.push(dictProductsYear[p]);
    }
    
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