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Home/ Questions/Q 5993447
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T23:40:35+00:00 2026-05-22T23:40:35+00:00

I would like to subset (filter) a dataframe by specifying which rows not (

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I would like to subset (filter) a dataframe by specifying which rows not (!) to keep in the new dataframe. Here is a simplified sample dataframe:

data
v1 v2 v3 v4
a  v  d  c
a  v  d  d
b  n  p  g
b  d  d  h    
c  k  d  c    
c  r  p  g
d  v  d  x
d  v  d  c
e  v  d  b
e  v  d  c

For example, if a row of column v1 has a “b”, “d”, or “e”, I want to get rid of that row of observations, producing the following dataframe:

v1 v2 v3 v4
a  v  d  c
a  v  d  d
c  k  d  c    
c  r  p  g

I have been successful at subsetting based on one condition at a time. For example, here I remove rows where v1 contains a “b”:

sub.data <- data[data[ , 1] != "b", ]

However, I have many, many such conditions, so doing it one at a time is not desirable. I have not been successful with the following:

sub.data <- data[data[ , 1] != c("b", "d", "e")

or

sub.data <- subset(data, data[ , 1] != c("b", "d", "e"))

I’ve tried some other things as well, like !%in%, but that doesn’t seem to exist.
Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T23:40:36+00:00Added an answer on May 22, 2026 at 11:40 pm

    The ! should be around the outside of the statement:

    data[!(data$v1 %in% c("b", "d", "e")), ]
    
      v1 v2 v3 v4
    1  a  v  d  c
    2  a  v  d  d
    5  c  k  d  c
    6  c  r  p  g
    
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