Question

I would like to SUM up one column, but based on different transaction types, and have those sums appear in one row only.

My SQL (SQL Server 2000) looks like this:

SELECT c.customername,
       CASE WHEN t.transactiontypekey IN (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19) THEN SUM(t.tranamount) ELSE 0 END as 'Tot-Exp',
       CASE WHEN t.transactiontypekey IN (20,21,22,23,30,32,34,36) THEN SUM(t.tranamount) ELSE 0 END as 'Tot-Rev',
       CASE WHEN t.transactiontypekey IN (31,33,35,37) THEN SUM(t.tranamount) ELSE 0 END as 'Tot-Fee'
FROM customers c, transactions t
WHERE c.customerkey = t.customerkey
GROUP BY c.customername, t.transactiontypekey
ORDER BY c.customername

In the above SQL, the transaction types are broken out into Expenses, Revenue and Fees and the output from above is showing as:

customernameTot-Exp  Tot-Rev    Tot-Fee
CUSTOMER1   13.3900    .0000      .0000
CUSTOMER1     .0000 549.0000      .0000
CUSTOMER1     .0000    .0000    60.0000
CUSTOMER1     .0000    .0000      .0000

How can I get my output to look like:

customername     Tot-Exp   Tot-Rev  Tot-Fee
CUSTOMER1         13.390    549.00   60.000

one row per customer with all of the totals of the ‘t.tranamount’ column in that one row only?

Answer 1

Sum the CASE expression itself;

SUM(CASE WHEN t.transactiontypekey IN (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19) THEN t.tranamount ELSE 0 END) as 'Tot-Exp',

And remove t.transactiontypekey from the the GROUP BY.