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Home/ Questions/Q 3492082
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T11:42:55+00:00 2026-05-18T11:42:55+00:00

I would like to take a string like so: <div>my div 1</div><p>para1</p><p>para2</p><p>para3</p><div>my div 2</div>

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I would like to take a string like so:

<div>my div 1</div><p>para1</p><p>para2</p><p>para3</p><div>my div 2</div>

and then remove all <p> nodes.

I’m having difficulty with this because I think that the string above has no context, and JQuery needs a context to work with to allow selectors to work:

var p = "<div>my div 1</div><p>para1</p><p>para2</p><p>para3</p><div>my div 2</div>"
var pj = $(p)

When I run the statement below in FireBug, I get no elements returned. Is this because the ‘p’ variable needs to be wrapped in another div for it to work? I want to be able to strip the elements from the string, even though it is not part of the DOM.

$("p",pj)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:42:56+00:00Added an answer on May 18, 2026 at 11:42 am

    You need .filter() to search elements at the same level, like this:

    $(pj).filter("p");
    

    $("p",pj) translates to $(pj).find("p") under the covers, that’s why it’s not finding anything, because the <p> elements are descendants of pj, they’re members. To be clear, jQuery doesn’t need them to be contained in anything, it’s a descendant vs non-descendant issue.


    The alternative approach is to add them to a temporary fragment and always use .find(), like this:

    var p = "<div>my div 1</div><p>para1</p><p>para2</p><p>para3</p><div>my div 2</div>"
    var pj = $('<div />').html(p);
    

    Then $("p",pj) would work.

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