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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:14:17+00:00 2026-05-11T17:14:17+00:00

I would like to try this code: public struct Direction { private int _azimuth;

  • 0

I would like to try this code:

public struct Direction
{
   private int _azimuth;

   public int Azimuth
   {
     get { return _azimuth; }
     set { _azimuth = value; }
   }       

   public Direction(int azimuth)
   { 
      Azimuth = azimuth
   } 
}

But it fails on compilation, I understand that struct need to init all its fields.
but i am trying to understand what happens under the CLR\IL hoods.
why it need all the fields before any other method\property\this etc.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:14:17+00:00Added an answer on May 11, 2026 at 5:14 pm

    Value Types are created on the stack (unless nested within a reference type) There is something about fields/locations on the stack that the CLR can’t guarantee that they will be zeroed out (contrary to fields/locations on the managed heap which are guaranteed to be zeroed out). Hence they must be written to before being read. Otherwise it’s a security hole.

    The struct’s default ctor (which takes no parameters and which you’re not allowed to explicitly specify) zeroes out all fields of a struct and hence you can use a struct after you do.

    new BimonthlyPairStruct()
    

    However when you implement your parameterized ctor, you must ensure that all fields have been initialized – which is required for the CLR to pass your code as safe/verified .

    See Also: CLR via C# 2nd Ed – Pg 188

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