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Home/ Questions/Q 7650379
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T11:14:16+00:00 2026-05-31T11:14:16+00:00

I would like to understand, why is it when I specify the number for

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I would like to understand, why is it when I specify the number for the method to sum up numbers it returns 21, but when i enter the value through scanner it gives me the correct value. For example number 3 should be 1 + 2 + 3 = 6 but its giving me 21, any ideas thanks.

public class sumInt
{

    public static void main(String[] args)
    {
        int i  = sumInt(3);
        int j  = sumInt(10);

        Scanner in = new Scanner (System.in);
        System.out.println("Please enter posiutive integer: ");
        int k = in.nextInt();

        System.out.println(sumInt(i));
        System.out.println(sumInt(j));
        System.out.println(sumInt(k));  
    }

    public static int sumInt(int n)
    {
        int sum = 0;
        for (int i = 0; i <= n; i++)
        {
            sum += i;

        }
        return sum;
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-31T11:14:17+00:00Added an answer on May 31, 2026 at 11:14 am

    You are actually summing up to 6 for i, your current code could also be written as:

    System.out.println(sumInt(sumInt(3)));
    

    You’ll need to print out i directly instead of calling sumInt on it again.

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