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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T20:30:50+00:00 2026-06-14T20:30:50+00:00

I would like to use a lambda that adds one to x if x

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I would like to use a lambda that adds one to x if x is equal to zero. I have tried the following expressions:

t = map(lambda x: x+1 if x==0 else x, numpy.array())
t = map(lambda x: x==0 and x+1 or x, numpy.array())
t = numpy.apply_along_axis(lambda x: x+1 if x==0 else x, 0, numpy.array())

Each of these expressions returns the following error:

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

My understanding of map() and numpy.apply_along_axis() was that it would take some function and apply it to each value of an array. From the error it seems that the the lambda is being evaluated as x=array, not some value in array. What am I doing wrong?

I know that I could write a function to accomplish this but I want to become more familiar with the functional programming aspects of python.

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  1. Editorial Team
    Editorial Team
    2026-06-14T20:30:52+00:00Added an answer on June 14, 2026 at 8:30 pm

    If you’re using numpy, you should be writing vectorised code:

    arr + (arr == 0)
    
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