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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T08:40:36+00:00 2026-05-12T08:40:36+00:00

I would like to write a java script which: When the page loads takes

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I would like to write a java script which:

  1. When the page loads takes the content of a <div> tag and
  2. Places that content on a popup page.

any ideas for the script?

I know how to navigate to the element but have no idea how to copy the content.

The content of the div will be something like this

        <div id="validationDiv">
        <div id="ctl00_Main_OTClaim1_valControls" class="errorpanel" style="color:Red;">
        <ul><li>Approver Name - required field.</li><li>Week Commencing Date - required field.</li><li>Summary of Hours Worked must be completed.</li><li>At least one item must be claimed to proceed.</li></ul>
    </div>
    </div>

where valadation div contains what i want to copy to the new window

cheers

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T08:40:36+00:00Added an answer on May 12, 2026 at 8:40 am
    window.onload = function() {
    
      var el = document.getElementById("ctl00_Main_OTClaim1_valControls");
      var html = "";
    
      if (el) {
        html = document.getElementById("ctl00_Main_OTClaim1_valControls").innerHTML;
        var xopen = window.open("about:blank");
        xopen.document.write(html);
      }
    }
    

    –UPDATE

    window.onload = function() {
    
      var el = document.getElementById("ctl00_Main_OTClaim1_valControls"); //the element you want expanded
      var html = "";
    
      if (el) {
        html = el.innerHTML;
        var xopen = window.open("about:blank");
        xopen.document.write(html);
      }
    }
    
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