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Home/ Questions/Q 8682947
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T21:54:36+00:00 2026-06-12T21:54:36+00:00

i would say that this code would provide the same output three times but

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i would say that this code would provide the same output three times but it does not:

import crcmod

#create CRC16 calculator
crc16 = crcmod.predefined.mkCrcFun('crc-16')

#wait for user input
#hstr = raw_input("enter hex commands, space separated: ")
hstr = '81 12 C0 00 01 05'
hex_series = hstr.replace(' ', '\\x')
hex_series_caps = hstr.capitalize().replace(' ', '\\x') #why is there difference?

print hex(crc16(hex_series))  # gives 0xd795 incorrect! + how can there be a 9???
print hex(crc16(hex_series_caps))  # gives 0x37b4 incorrect!
print hex(crc16('\x81\x12\xC0\x00\x01\x05')) # gives 0x815b correct!

please explain!

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  1. Editorial Team
    Editorial Team
    2026-06-12T21:54:37+00:00Added an answer on June 12, 2026 at 9:54 pm

    Let’s open a Python prompt…

    >>> hstr
    '81 12 C0 00 01 05'
    >>> hex_series
    '81\\x12\\xC0\\x00\\x01\\x05'
    >>> hex_series_caps
    '81\\x12\\xc0\\x00\\x01\\x05'
    

    As you can see, none of the strings are the strings you want. Replacing spaces with "\\x" just inserts a bunch of backslashes and x characters into your string, it does not do any escaping.

    An escape sequence like '\x63' will become 'c', but only if you write it that way in the source code. Escape sequences do not happen after string manipulation, reading strings, or almost anything else. For example,

    >>> '\x63'
    'c'
    >>> '\\' + 'x63'
    '\\x63'
    

    Try this instead:

    import base64
    data = base64.b16decode(hstr.replace(' ', ''))
    print hex(crc16(data))
    
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