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Home/ Questions/Q 7814009
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T05:03:36+00:00 2026-06-02T05:03:36+00:00

I write a program in c++ with two files. main.cpp #include var.hpp #include <iostream>

  • 0

I write a program in c++ with two files.

main.cpp

#include "var.hpp"
#include <iostream>
using namespace std;
using namespace YU;

int main()
{
    string god = "THL";
    age = 10;
    cout << age << endl;
    cout << god << endl;
    return 0;
}

var.hpp

#ifndef __VAR_H__
#define __VAR_H__

#include <string>

namespace YU
{
    int age;
    string name;
}

#endif

When I compilered it, It’get wrong.

the wrong infomation is:

In file included from main.cpp:1:0:

var.hpp:9:5: Error: ‘string’ is not a type name

I don’t know why,I had include <string> head file, but it still dosen’t work.

I write this code just for practice, not for work.

thank you!

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  1. Editorial Team
    Editorial Team
    2026-06-02T05:03:37+00:00Added an answer on June 2, 2026 at 5:03 am

    The problem is the namespace of string in var.hpp. string is the std namespace, but you are not telling the compiler that. You could fix it by putting using namespace std; in var.hpp, but the following is a better solution as it doesn’t clutter the global namespace with other things from std:

    #ifndef __VAR_H__
    #define __VAR_H__
    
    #include <string>
    
    namespace YU
    {
        int age;
        std::string name;
    }
    
    #endif
    
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