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Home/ Questions/Q 825107
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:12:07+00:00 2026-05-15T03:12:07+00:00

I write this code for checking: var num = $(#knum).val(); if (isNaN(parseInt(num))) { $(#errorknum).html(Please

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I write this code for checking:

var num = $("#knum").val();
        if (isNaN(parseInt(num))) {
            $("#errorknum").html("Please define a number.");
        }
        else {
            if (num < 1 | num > 249) {
                $("#errorkrnum").html("your number must be less then 249 and can be greater than 1");
            }
            else {
                $("#errorknum").html("");
            }

Everything is fine but, for example, when the user type 1242fdlfldsf means it is 1242 but she accept it. How can I dishandle this value by code like for example: 23232dkfj

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:12:08+00:00Added an answer on May 15, 2026 at 3:12 am

    parseInt() should always be used with the second argument, in order to tell it that you expect a base-10 number:

    parseInt(num, 10)
    

    Also, you don’t save its results so you are comparing strings.

    And the single | is a bitwise operator. You probably want ||.

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