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Home/ Questions/Q 7162265
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:42:23+00:00 2026-05-28T13:42:23+00:00

I wrote a code in python which looks like: maplist=[{}]*11 mylist=[0]*11 maplist[0][‘this’]=1 print maplist

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I wrote a code in python which looks like:

maplist=[{}]*11
mylist=[0]*11
maplist[0]['this']=1
print maplist

When I print maplist the output is :

[{'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}, {'this': 1}]

Expected is:

[{'this': 1}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}]

rather than only the first element of the list should have this key in the map. What is causing this problem?

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:42:24+00:00Added an answer on May 28, 2026 at 1:42 pm

    When you do the following:

    maplist=[{}]*11
    

    you end up with eleven references to the same dictionary. This means that when you modify one dictionary, they all appear to change.

    To fix, replace that line with:

    maplist=[{} for in xrange(11)]
    

    Note that, since 0 is a scalar, the next line is fine as it is:

    mylist=[0]*11
    
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