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Home/ Questions/Q 6324799
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T16:46:26+00:00 2026-05-24T16:46:26+00:00

I wrote a custom MSBuild task which calls SubWCRev.exe , an executable which (typically)

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I wrote a custom MSBuild task which calls SubWCRev.exe, an executable which (typically) resides in C:\Program Files\TortoiseSVN\bin, whether it’s 32 or 64 bits, since TortoiseSVN provides both versions.

The problem is, Visual Studio 2010 only has a 32 bit version. So when my colleagues with a 64 bit box try to build using my shiny new task, $(ProgramFiles) resolves to C:\Program Files(x86) and it explodes saying that SubWCRev.exe cannot be found. Because they have the 64 bit version of TortoiseSVN, which lives in C:\Program Files!

Is there a better solution than hardcoding C:\Program Files in my msbuild script, or having everyone use the 32 bit version of TortoiseSVN? (Actually it’s a C# project, I tinkered with the MSBuild code a bit)

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  1. Editorial Team
    Editorial Team
    2026-05-24T16:46:26+00:00Added an answer on May 24, 2026 at 4:46 pm

    Take a look it this:

    <Project ToolsVersion="4.0" DefaultTargets="PrintValues" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
    
      <Target Name="PrintValues">
        <PropertyGroup>
          <MyProgramFiles>$(ProgramW6432)</MyProgramFiles>
          <MyProgramFiles Condition="$(MyProgramFiles) == ''">$(ProgramFiles)</MyProgramFiles>
        </PropertyGroup>
    
        <Message Text="MyProgramFiles: $(MyProgramFiles)"/>
      </Target>
    
    </Project>
    

    This lets MyProgramFiles resolve to “C:\Program Files” for both 32 and 64 bit Windows (The ProgramW6432 environment variable is empty on non-64 bit versions of Windows).

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