Question

I wrote a php search for a table in mysqli and it works fine but i want to show the correct message to user if no result were found.

here is my current code:

$search_string=$_GET["design"];

$connect= mysqli_connect("mysql.myhost.com","abc","123456","mydb_db");
$query="select * from product where product_design like '%$search_string%'";
$rows= @mysqli_query($connect,$query) or die("Error: ".mysqli_error($connect));
if ($rows!=null)//I put this if to check if there is any result or not but its not working
{

while(($record=mysqli_fetch_row($rows))!=null)
{
    .
            .//i have working code for showing the result here
            .
}   
mysqli_close($connect);
}
else{
echo"no result found";
}

could you please help me what is wrong , even when i search for something which is not exist in the db still the program not displaying “no result found”

Thank you

Answer 1

What you need is mysqli_num_rows specifically the mysqli_result::num_rows bit. This adds a num_rows property to mysqli result sets. This means you can do

$rowCount = $rows->num_rows

There’s also a non-OO equivalent …

$rowCount = mysqli_num_rows($rows);

(The difference is purely one of coding style)

Use one of these to determine how many records are returned and output the appropriate messages.