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Home/ Questions/Q 8607301
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:19:12+00:00 2026-06-12T03:19:12+00:00

I wrote a query but I got following error, Any ideas ?! Error :

  • 0

I wrote a query but I got following error, Any ideas ?!

Error :

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in E:\AppServ\www\admin\index.php on line 545

Code :

                    require_once '../_db/databaseConnect.php';
                    $db = new databaseConnect();
                    $db->connect();
                    $queryResult = mysql_query("(SELECT * FROM tabelcomments WHERE publishStatus = 2) UNION (SELECT appTitleFa FROM tableapps WHERE appID = '$appID');");
                    for ($dataCnt = 0; $dataCnt < mysql_num_rows($queryResult); $dataCnt++) 
                      {
                         //codes...
                      }
                    $db->close();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T03:19:14+00:00Added an answer on June 12, 2026 at 3:19 am

    Both parts of a UNION should return the same amount and same type of columns.

    Most likely, your tabelComments table contains more columns than the single column returned from the tableApps table in the second part of your union.

    You can fix this by explicitly selecting the appropriate column(s) from tableComments or add dummy columns to the UNIONpart.

    Example

    SELECT NULL as dummycol1, comment FROM tablecomment
    UNION SELECT appTitleFa, NULL as dummycol2 FROM tableapps
    
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