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Home/ Questions/Q 3443870
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T08:50:40+00:00 2026-05-18T08:50:40+00:00

I wrote a script for a Linux bash shell. One line takes a list

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I wrote a script for a Linux bash shell.

One line takes a list of filenames and sorts them. The list looks like this:

char32.png char33.png [...] char127.png

It goes from 32 to 127.
The default sorting of ls of this list is like this

char100.png char101.png [...] char32.png char33.png [...] char99.png

Luckily, there is sort, which has the handy -V switch which sorts the list correctly (as in the first example).

Now, I have to port this script to OSX and sort in OSX is lacking the -V switch.

Do you have a clever idea of how to sort this list correctly?

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  1. Editorial Team
    Editorial Team
    2026-05-18T08:50:41+00:00Added an answer on May 18, 2026 at 8:50 am

    Do they all start with a fixed string (char in your example)? If so:

    sort -k1.5 -n
    

    -k1.5 means to sort on the first key (there’s only one key in your example) starting from the 5th character, which will be the first digit. -n means to sort numerically. This works on Linux too.

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