Question

I wrote a simple regex-script in PHP:

<?php  
$string = "\section{Test 1} 
sdfgsdfg";  
$regex = "@\\section{(.*?)}@U";  
$replace = "$1jksdfahlkjh";  
$newString = preg_replace ($regex, $replace, $string, -1 );  
?> 

See: http://regexp-tester.mediacix.de/t287

using

echo $newString;

only give me

\section{Test 1} sdfgsdfg

Regex-patterns like

$bbcode = array(

"/\[b\](.*?)\[\/b\]/is" => "<strong>$1</strong>",
"/\[u\](.*?)\[\/u\]/is" => "<u>$1</u>",
"/\[url\=(.*?)\](.*?)\[\/b\]/is" => "<a href='$1'>$2</a>"

);
$text = "[b]Text[/b][u]Text[/u]";

$text = preg_replace(array_keys($bbcode), array_values($bbcode), $text);
echo $text;

works great. Is there any solution? I don’t want to write an whole LaTeX-Parser, but I want to replace those “\section{…}”-Strings

Answer 1

You need to escape the \‘s, because otherwise they will already be treated as an escape by php itself and then stripped:

$regexp = "@\\\\section{(.*)}@";

The U modifier is unnecessary, as that makes the .*? greedy again, so you are reversing the reversing. Just .* works just as well.