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Home/ Questions/Q 7516079
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Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T01:01:14+00:00 2026-05-30T01:01:14+00:00

I wrote a stupid solution for this, any better recipe? As you can see

  • 0

I wrote a stupid solution for this, any better recipe?
As you can see lots of useless conversions there.

package main

import (
    "fmt"
    "strconv"
    "math"
)

func conv(str string) int {
    l := len(str)
    result := 0.0
    for i,n := range str {
        number,_ := strconv.Atof64(string(n))
        result += math.Exp2(float64(l-i-1))*number
    }
    return int(result)
}

func main() {
    fmt.Println(conv("1001"))
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T01:01:16+00:00Added an answer on May 30, 2026 at 1:01 am

    You want the strconv.ParseInt function, which converts from an arbitrary base, into a given bit size.

    package main
    
    import (
        "fmt"
        "strconv"
    )
    
    func main() {
        if i, err := strconv.ParseInt("1001", 2, 64); err != nil {
            fmt.Println(err)
        } else {
            fmt.Println(i)
        }
    }
    

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