Question

I wrote a update function when user logins and logouts, the code is

function update_status_offline($id) {
$id = $_SESSION['id'];
mysql_query("UPDATE users SET status = 0 WHERE id = $id"); }

And the same for online status, everything works great but when I removed

header('Location: ../');

It show me following error:

Warning: Missing argument 1 for update_status_offline() (…)

What could be wrong in the code ?

Answer 1

You are not passing the argument to the function

If you have:

update_status_offline();

it needs to be changed to:

update_status_offline($id);

or alternatively remove $id from the function as it seems it is already being set.

function update_status_offline(){
    $id = $_SESSION['id'];
    mysql_query("UPDATE users SET status = 0 WHERE id = $id"); 
}