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Home/ Questions/Q 6320309
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T15:56:54+00:00 2026-05-24T15:56:54+00:00

I wrote some statements like below: os.system(cmd) #do something subprocess.call(‘taskkill /F /IM exename.exe’) both

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I wrote some statements like below:

os.system(cmd) #do something
subprocess.call('taskkill /F /IM exename.exe')

both will pop up a console.

How can I stop it from popping up the console?

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  1. Editorial Team
    Editorial Team
    2026-05-24T15:56:54+00:00Added an answer on May 24, 2026 at 3:56 pm

    The process STARTUPINFO can hide the console window:

    si = subprocess.STARTUPINFO()
    si.dwFlags |= subprocess.STARTF_USESHOWWINDOW
    #si.wShowWindow = subprocess.SW_HIDE # default
    subprocess.call('taskkill /F /IM exename.exe', startupinfo=si)
    

    Or set the creation flags to disable creating the window:

    CREATE_NO_WINDOW = 0x08000000
    subprocess.call('taskkill /F /IM exename.exe', creationflags=CREATE_NO_WINDOW)
    

    The above is still a console process with valid handles for console I/O (verified by calling GetFileType on the handles returned by GetStdHandle). It just has no window and doesn’t inherit the parent’s console, if any.

    You can go a step farther by forcing the child to have no console at all:

    DETACHED_PROCESS = 0x00000008
    subprocess.call('taskkill /F /IM exename.exe', creationflags=DETACHED_PROCESS)
    

    In this case the child’s standard handles (i.e. GetStdHandle) are 0, but you can set them to an open disk file or pipe such as subprocess.DEVNULL (3.3) or subprocess.PIPE.

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