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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:00:18+00:00 2026-05-13T21:00:18+00:00

I wrote something like this: instance Functor (Either e) where fmap _ (Left a)

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I wrote something like this:

instance Functor (Either e) where

   fmap _ (Left a) = Left a

   fmap f (Right b) = Right (f b)

How do I do the same if I want fmap to change the value only if it’s Left?

I mean, what syntax do I use to indicate that I use type Either _ b instead of Either a _?

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:00:19+00:00Added an answer on May 13, 2026 at 9:00 pm

    I don’t think there’s a way to do that directly, unfortunately. With a function you can use flip to partially apply the second argument, but that doesn’t work with type constructors like Either.

    The simplest thing is probably wrapping it in a newtype:

    newtype Mirror b a = Mirrored (Either a b)
    
    instance Functor (Mirror e) where
        fmap _ (Mirrored (Right a)) = Mirrored $ Right a
        fmap f (Mirrored (Left b)) = Mirrored $ Left (f b)
    

    Wrapping with newtype is also the standard way to create multiple instances for a single type, such as Sum and Product being instances of Monoid for numeric types. Otherwise, you can only have one instance per type.

    Additionally, depending on what it is you want to do, another option is to ignore Functor and define your own type class like this:

    class Bifunctor f where
        bimap :: (a -> c) -> (b -> d) -> f a b -> f c d
    
    instance Bifunctor Either where
        bimap f _ (Left a)  = Left  $ f a
        bimap _ g (Right b) = Right $ g b
    
    instance Bifunctor (,) where
        bimap f g (a, b) = (f a, g b)
    

    Obviously, that class is twice as much fun as a regular Functor. Of course, you can’t make a Monad instance out of that very easily.

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