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Home/ Questions/Q 3852336
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T17:18:09+00:00 2026-05-19T17:18:09+00:00

I wrote the following, but its saying that its the ‘wrong datatype’. Could someone

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I wrote the following, but its saying that its the ‘wrong datatype’.

Could someone tell me where im going wrong.

$newQuery = mysql_query("SELECT * FROM table WHERE left_id='$authId'");
$catid = mysql_fetch_array($newQuery);

if(in_array("99", $catId)){
    // A Director
} else {
    // A Researcher
}

Cheers,

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  1. Editorial Team
    Editorial Team
    2026-05-19T17:18:10+00:00Added an answer on May 19, 2026 at 5:18 pm

    You are assigning the row to $catid and later using $catId. Notice the capital “I”. You also need to make sure $catId is an array because mysql_fetch_array will return FALSE if there are no rows.

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