I wrote the following code
var=0
cat $file | while read line do
var=$line
done
echo $var
Now as I understand it the pipe (|) will cause a sub shell to be created an therefore the variable var on line 1 will have the same value on the last line.
However this will solve it:
var=0
while read line do
var=$line
done < $file
echo $line
My question is why does the redirect not cause a subshell to be created, or if you like why does pipe cause one to be created?
Thanks
The
catcommand is a command which means it needs its own process and has its own STDIN and STDOUT. You’re basically taking the STDOUT produced by thecatcommand and redirecting it into the process of the while loop.When you use redirection, you’re not using a separate process. Instead, you’re merely redirecting the STDIN of the while loop from the console to the lines of the file.
Needless to say, the second way is more efficient. In the old Usenet days before all of you little whippersnappers got ahold of our Internet (_Hey you kids! Get off of my Internet!) and destroyed it with your fancy graphics and all them web page, some people use to give out the Useless Use of Cat award for people who contributed to the comp.unix.shell group and had a spurious
catcommand because the use ofcatis almost never necessary and is usually more inefficient.If you’re using a
catin your code, you probably don’t need it. Thecatcommand comes from concatenate and is suppose to be used only to concatenate files together. For example, when we use to use SneakerNet on 800K floppies, we would have to split up long files with the Unix split command and then usecatto merge them back together.