Question

I wrote the following:

Object.prototype.length = function(){
    var count = -1;
    for(var i in this) count++;
    return count;
}

It works. But when I execute my page, even without using this function, Firebug tells me that jQuery’s .appendTo() is no longer a function. Why would this be?

Answer 1

That prototype extension is breaking the $.each method, because this method detects between arrays and objects using the length property (in jQuery 1.4.2):

// core.js Line 533
each: function( object, callback, args ) {
    var name, i = 0,
        length = object.length, // <--- your function from Object.prototype
        isObj = length === undefined || jQuery.isFunction(object);
//...

As you can see, the isObj variable will be true only if it doesn’t contains a length property (or the property value is undefined).

If isObj is false, jQuery will try to iterate using a normal for loop:

for ( var value = object[0];
    i < length && callback.call( value, i, value ) !== false; value = object[++i] ) {}

Then, the appendTo method is created using $.each, that’s why is not defined:

//...
jQuery.each({
    appendTo: "append",
    prependTo: "prepend",
    insertBefore: "before",
    insertAfter: "after",
    replaceAll: "replaceWith"
},
//...

I will always recommend to stay away from extending Object.prototype, when you extend this prototype ALL objects receive those additional properties.

This is especially problematic since when you iterate over the properties of the object
these new properties appear, causing all sorts of unexpected behavior.