Question

I wrote the following piece of code on codepad but I do not understand how/why it should compile.

#include<iostream>

using namespace std;

typedef double dObject;
typedef int iObject;
typedef void (*swapfuncptr)(dObject, dObject);

void swap(dObject a,dObject b) {
cout << a << " " << b << endl;
dObject tmp;
tmp = a;
a = b;
b = tmp;
cout << a << " " << b << endl;
}
int main() {

double a = 7.5, b = 5.3;
swapfuncptr swapptr1;
swapptr1 = &swap;
swapptr1(a, b);

int c = 3, d = 2;
swapfuncptr swapptr2;
swapptr2 = &swap;
swapptr2(c, d);

swapfuncptr swapptr3;
swapptr3 = &swap;
swapptr3('r', 'd');
return 0;
}

So dobject is only for doubles for the functions with integer parameters also work. I do not get how this works.

Can someone please explain.

Thanks
S

Answer 1

int is implicitly convertable to double. Creating a typedef for double does not change that.