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Home/ Questions/Q 6391829
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T03:44:14+00:00 2026-05-25T03:44:14+00:00

i wrote the following program #include <stdio.h> main() { int i = 2; float

  • 0

i wrote the following program

 #include <stdio.h>

 main()
 {
 int i = 2;
 float c = 4.5;
 printf("%d\n",c);
 printf("%f\n",i);
 return 0;
 }

though i know this is the wrong practice,when i run the program i got the answer as

0
4.500000

but when i exchanged the printf statements a little bit this way

#include <stdio.h>

main()
{
int i = 2;
float c = 4.5;
printf("%f\n",i);
printf("%d\n",c);
return 0;
}

the output was

0.000000
0

i couldn’t understand whats happening ,any one pls explain me.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T03:44:14+00:00Added an answer on May 25, 2026 at 3:44 am

    printf doesn’t convert it’s arguments. It’s looking at the memory containing a float and printing it as if it were an integer – it’s like taking an MP3 file and asking word to open it as if it were a doc.

    A floating point number is stored in a completely different way in memory to an integer – it’s not just an integer with some decimal points

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