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Editorial Team
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Asked: 2026-05-22T19:06:35+00:00

I wrote this: <head> <script src=http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js></script> <script> $(div.productInfo).wrap(<div id=’productDetails’></div>); </script> </head> <body> <div class=productInfo>Whatever.</div>

  • 0

I wrote this:

<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
    <script>
        $("div.productInfo").wrap("<div id='productDetails'></div>");
    </script>
</head>

<body>
     <div class="productInfo">Whatever.</div>
</body>

And it didn’t work?.
Thanks.

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1 Answer

  1. Editorial Team

    your element hasn’t been rendered when your script runs… try this:

    <script>
    $(document).ready(function(){
        $("div.productInfo").wrap("<div id='productDetails' />");
    });
</script>
    • 0