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Home/ Questions/Q 929393
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:09:51+00:00 2026-05-15T20:09:51+00:00

I wrote this routine to order items, keep only unique items, where it takes

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I wrote this routine to order items, keep only unique items, where it takes in an array of type T, and the size of the array. It returns the new size of the array after processing.

template <class T>
int reduce(T array[], int size) {
    T *begin = array;
    T *end = array + size;
    sort(begin, end);
    T *end_new = unique(begin, end);
    return end_new - array;
}

My question is I was expecting it to sort const char *data like

{"aa", "bb", "bc", "ca", "bc", "aa", "cc", "cd", "ca", "bb"};
into //aa bb bc ca cc cd

However it does it the opposite way, : “cd cc ca bc bb aa”
Why does it do that? Does it not use the standard string comparisons? If I wanted to, how could I alter it so it would order const char * alphabetically? thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:09:52+00:00Added an answer on May 15, 2026 at 8:09 pm

    sort() uses operator< per default, which would just compare the addresses in your case.

    If you want to sort C-strings, you have to pass a comparator to sort(). To do this generically you can let the user pass a comparator, use specialization on a comparator function or a combination of these:

    template<class T> bool my_comp(T a, T b) {
        return a < b;
    }
    
    template<> bool my_comp<const char*>(const char* a, const char* b) {
        return std::strcmp(a, b) < 0;
    }
    
    template<class T, class Comp> 
    int reduce(T array[], size_t size, Comp comp = my_comp<T>) {
        // ...
        std::sort(begin, end, comp);
        // ...
    }
    
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