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Home/ Questions/Q 6901941
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T07:44:12+00:00 2026-05-27T07:44:12+00:00

I wrote this small C program: #include <stdio.h> #include <stdlib.h> int main() { FILE

  • 0

I wrote this small C program:

#include <stdio.h>
#include <stdlib.h>

int main()
{
 FILE * fp;
 fp = fopen("data.txt","w");
 fprintf(fp,"%d",578); 
 return 0;
}

Then I analyzed data.txt using xxd -b. I was expecting that I will see the 32 bit representation of 578 instead I saw the ASCII representation of 578:

xxd -b data.txt
0000000: 00110101 00110111 00111000                             578

Why is that? How do I store the 32 bit representation of 578 (01000010 00000010 00000000 00000000) assuming little endian?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T07:44:13+00:00Added an answer on May 27, 2026 at 7:44 am

    Use fwrite:

    uint32_t n = 578;
    fwrite(&n, sizeof n, 1, fp);
    

    fprintf is for formatted output, whence the trailing f.

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