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Home/ Questions/Q 6841091
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:55:26+00:00 2026-05-26T23:55:26+00:00

i2c_receiveData(sDevice *psDevice, byte_t *pbBuffer, uint16_t *puiLen) { . . //extract the packet data length

  • 0
i2c_receiveData(sDevice *psDevice, byte_t *pbBuffer, uint16_t *puiLen)
{
.
.    
//extract the packet data length
unFrameLen = (*(pbBuffer+1) << 8) | *(pbBuffer + 2);
if(unFrameLen > *puiLen)
unFrameLen=*puiLen;
.
.
}

Here how this statement is finding Frame Length?

unFrameLen = (*(pbBuffer+1) << 8) | *(pbBuffer + 2);

Here pbBuffer is a pointer to unsigned char array.

calling function was,

i2c_receiveData(psDevice, prgDataRecv, &unRegLen);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:55:27+00:00Added an answer on May 26, 2026 at 11:55 pm

    In this case, it appears the “frame length” is stored at offset 1 into the passed buffer.

    It also appears that it is a 16-bit integer.

    In order to get a usable 16-bit integer you must unpack from the buffer. It would be better to cast and use htons/ntohs instead, but I presume the architecture is well-known and portability isn’t a concern.

    For an input of, say, pbBuffer = {0, 1, 2}, this ends up being:

    (1 << 8) | 2;
    

    … which gives:

    (00000001b << 8) | 00000010b
    

    … shifting 1b left 8 bits gives:

    100000000b
    

    … and OR-ing with 10b:

    100000010b
    

    Now you have a 16-bit integer from the two 8-bit integers in pbBuffer[1..2]:

    100000010b = 0x102
    
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