Question

Iam using django decorators in my project.
Iam using multiple views with arguments and i need to call 1 decorator.

I want only one view to call with its arguments once. But the decorators giving the values of every views wherever i used the decorator.

I want the argument belong to the particular views which i called.

My views and decorator as:

def d(msg='my default message'):
    def decorator(func):
        print msg
        def newfn(request, **kwargs):
            return func(request, **kwargs)
        return newfn
    return decorator

@d('This is working')
def company_add(request):
   return ...

@d('Dont come')
def company_list(request, comp_id = None):
   return ...

If i call company_add views, Iam getting Output as :

This is working
Dont come

But my expected result is

This is working.

Anyone help me to print only the argument belong to the particular views.

Answer 1

When you wrap function with @d(arg), you actually run the body of the d function with msg=arg before running decorated function and of course print the msg. You can place the print statement somewhere else, for example:

def d(msg='my default message'):
    def decorator(func):
        def newfn(request, **kwargs):
            print msg
            return func(request, **kwargs)
        return newfn
    return decorator